A rectangular pool is twice as long as it is wide. What are the
dimensions of the pool if the
perimeter is 48 yd?

length * width = 16 yd * 8 yd

or

length = 16 yd

width = 8 yd

Step-by-step explanation:

take the rectangular pool to have sides a (length) and 2a (width).

we are told that the length is as twice as its width, therefore,

Perimeter is given by (a + 2a) × 2 = 48 yd

Divide both sides by 2 ⇒ ⇒ a + 2a = 24 yd

⇒3a = 24 yd

Divide both sides by 3 ⇒ ⇒ a = 8 yd

therefore, the width of the pool is 8 yd and its length is 16 yd (Twice as long as it is wide)

answer:  

step-by-step explanation:

odd numbers are only divisible by 1 and itself.

even numbers are divisible by more than 1 and itself.

for example 6 is even because it is divisible by more than 1 and its self. 1 x 6= 6 ; 2 x 3= 6

and 7 is odd because only 7 x 1 equals seveb