The line a bus arrives at the bus stop every 25 minuetes, and the line B busarrived every 15 minuetes both are at the bus stop right now. In how many minutes will both be at the bus stop again

75 minutes.

Step-by-step explanation:

Given that the line a bus arrives at the bus stop every 25 minuetes, and the line B busarrived every 15 minuetes both are at the bus stop right now.

In how many minutes will both be at the bus stop again?

We can achieve that by finding the LCM of 25 and 15

The LCM of both will be 3, 5 and 5

That is, 3 × 5 × 5 = 75 minute.

Therefore, both will be at the bus stop again in the next 75 minutes or 1 hour 15 minutes.

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

x/3-10=8

x/3=18

x=48