In a different plan for area codes, the first digit could be any number from 2 through 5, the second digit was either 2, 3, 4, or 5, and the third digit could be any number except 4, 5, or 8. With this plan, how many different area codes are possible?

Step-by-step explanation:

First digit 2,3,4,5 = 4 different digits.

Second digit 2,3,4,5 = 4 different digits.

Third digit = 1,2,3,6,7,9 = 6 different digits.

Total number of possibilities = 4*4*6 = 96

maximum area = xy = (16)(32) = 512 ft2

to maximize the area of the garden, the side of the fence parallel to the side of the house should be 32 ft long, and the other two sides should both have length 16 ft.'

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da freeck kinda math is this just drop out

step-by-step explanation: