A rectangular garden has a perimeter of 578 yds. The length is one more than three times the width.
Find the dimensions of the garden.

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

where

l is the length

w is the width

From the question

Perimeter = 578 yds

The statement

The length is one more than three times the width is written as

l = 1 + 3w

Substitute the expression into the above formula and solve for the width

That's

578 = 2(1 + 3w) + 2w

578 = 2 + 6w + 2w

8w = 576

Divide both sides by 8

w = 72

Substitute w = 72 into l = 1 + 3w

That's

l = 1 + 3(72)

l = 216 + 1

l = 217

Therefore the dimensions are

length = 217 yd

width = 72 yd

Hope this helps you

part 1 answer = 8

part 2 answer = 72

step-by-step explanation:

part 1 explanation = add all of the numbers, then divide by how many numbers you have. so, 200/25 = 8.

part 2 explanation = not gonna lie, this is hard to explain, so just google how to do it.

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet