A hot air balloon is flying above Groveburg. To the left side of the balloon, the balloonist measure the angle of depression to the Groveburg soccer fields to be 20° 15'. To the right side of the balloon, the balloonist measures the angle of depression to the high school football field to be 62° 30'. Find the distance from the balloon to the soccer fields

Solution : 3.6 miles

Step-by-step explanation:

The first step in solving this problem is to convert 15' to degrees --- (1) . 15' is represented as 15 minutes, so to convert to degrees we have 15 / 60 = 0.25°. Adding 20 + 15' we should get 20 + 0.25 = 20.25 (degrees).

Now remember that on the right side we have the football field, 62° 30'. Let's convert that 30' into degrees --- (2). 30 / 60 = 0.5, and 62 + 0.5 = 62.5.

Using both this information we can calculate the angle from the balloon to the horizontal. That would be 180 - 20.25 - 62.5 = 97.25°. Therefore the distance from the balloon to the soccer fields would be as follows,

distance / sin(62.5) = 4 / sin(97.25)

Let distance = x ...

x / sin(62.5) = 4 / sin(97.25),

x / 0.88701083317 = 4 / 0.99200494968,

x * 0.99200494968 = 4 * 0.88701083317,

x * 0.99200494968 = 3.548,

x = ( About ) 3.5766 miles

Given the options the distance from the balloon to the soccer fields would be 3.6 miles.

x ≥ 18 is your answer

step-by-step explanation:

let "a number" = x

(2/3)x + 17 ≥ 29

isolate the variable (x). do the opposite of pemdas (parenthesis, exponent (& root), multiplication, division, addition, subtraction).

first, subtract 17 from both sides.

(2/3)x + 17 (-17) ≥ 29 (-17)

(2/3)x ≥ 29 - 17

(2/3)x ≥ 12

next, multiply 3/2 to both sides to isolate the x

(3/2)(2/3)x ≥ 12(3/2)

x ≥ 12(3/2)

simplify. multiply, then divide

x ≥ (12 * 3)/2

x ≥ (36)/2

x ≥ 18

x ≥ 18 is your answer

~

the domain of a function is the set of input values, x , for which a function is defined. the domain is shown in the left oval in the picture below. the function provides an output value, f(x) , for each member of the domain.