Use the figure to the right to find the value of PT. T is the midpoint of PQ. PT = 5x +2 and TQ = 7x-6
PT=
(Simplify your answer.)

22

Step-by-step explanation:

Given that T is the midpoint of line PQ, segments PT = 5x + 2, and TQ = 7x - 6 that are formed would be equidistant or congruent. PT = TQ.

Therefore:

Let's find the value of x

Rearrange the equation, so that the terms having x would be on your left, while those without x would be on your right.

Divide both sides by -2

Plug in the value of x into the expression, 5x + 2, to find PT.

PT = 5(4) + 2 = 22.

x = central angle apc = measure of minor arc ac

the two angles x and 30 add to 180, so x+30 = 180 and x = 180-30 = 150. the measure of minor arc ac is 150 degrees.

what we need to do from here is find the circumference and then multiply it by x/360 since there are 360 degrees in a circle. in this case, x = 150, so x/360 = 150/360 = 15/36 = 5/12. the shortest distance along the curve from a to c is 5/12 of the distance around the entire circle (aka circumference)

c = circumference

c = pi*d

c = pi*24

c = 24pi

now multiply this by 5/12 to get

distance along minor arc ac = (5/12)*(circumference)

distance along minor arc ac = (5/12)*(24pi)

distance along minor arc ac = 10pi

the formula you can use is

l = (x/360)*pi*d

with

l = length of minor arc

x = central angle

d = diameter

which essentially is the steps we took though a bit differently.