Find the values for k so that the intersection of x=2k and 3x+2y=12 lies in the first quadrant.

Values of k can be 0, 1, or 2 such that intersection of the given lines lie in the 1st quadrant.

Step-by-step explanation:

Given two lines:

and

To find:

Values of 'k' such that the intersection of given two lines lie in the first quadrant.

Solution:

In 1st quadrant, the values of and both are positive.

So, let us find out intersection of the two lines.

Intersection of the two lines can be found by solving the two equations for the values of and .

Given that to be in the first quadrant, the value of k must be positive.

Let us put in the equation to find the intersection point.

For y to be positive:

So, values of k can be 0, 1, or 2 such that intersection of the given lines lie in the 1st quadrant.

answer: the anser is 3

step-by-step explanation:

c- 2o is equal to 9