Every morning there is an 70% chance that I get to the bus on times. if each morning is independent of the others, what is the probability that I get to the bus on times at least 4 times in 5 days? a 0.04437
b. 0.3915
c. 0.05220
d 0.5282
e 0.9657

d 0.5282

Step-by-step explanation:

Given the following :

Probability of getting to the bus on time = 70% = P = probability of success = 0.7

(1 - p) = probability of failure = 0.3

Number of trials(n) = 5 days

Number of sucesses (r) = atleast 4 days : >= 4

This is a binomial probability problem

P(r) = nCr × P^r × (1 - P)^(n - r)

P(X >=4) = P(4) + P(5)

P(4) = 5C4 × (0.7)^4 × (0.3)^1 = 0.36015

P(5) = 5C5 × (0.7)^5 × (0.3)^0 = 0.16807

P(4) + P(5) = 0.36015 + 0.16807 = 0.52822

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.

solve systems of equations by graphing. a system of linear equations contains two or more equations e.g. y=0.5x+2 and y=x-2. the solution of such a system is the ordered pair that is a solution to both equations. to solve a system of linear equations graphically we graph both equations in the same coordinate system