Find the x-intercepts of the parabola.

g(x)=−x2−6x−5

 The x intercepts are -1 and -5  or  (-1,0)   and ( -5,0)

Step-by-step explanation:

Finding the x intercepts of  a parabola is the same as finding the roots of a parabola because the x intercept is when y or g(x) is equal to zero. So set the equation equal zero.

         First  divide each term by 0 to get the largest degree coefficient to equal 0.

x^2 + 6x +5 = 0         Now find two numbers that their product is 5 and their sum is 6.  The numbers 5 and 1 works out because the 5 times 1 is 5 and 5 plus 1 is 6.

Rewrite the whole equation as

x^2 + 1x+5x +5 = 0     Now factor the left side by grouping

x(x+1) 5(x+1) = 0         Factor out x+1

(x+1) (x+5) = 0       Now use the zero product by setting each of them equal zero.

x+ 1 = 0    or    x+5 = 0

    -1    -1               -5  -5

x = -1      or  x = -5

second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.