How many pennies could you have if: When you Break de Pennies into groups of 2, you have 1 penny left over, AND when you break the pennies into groups of 3, and you have 1 penny left over, AND when you break the pennies into groups of 5, you have 1 penny left?

The answer is 31 pennies

Step-by-step explanation:

we have to find a number that gives a remainder of 1 when divided by both 2, 3 and 5.

The easiest way to do this is to list the factors of 5, add 1 to it, and test them until we find the one with a remainder of 1 by all three divisors. This is done as follows:

1) factor: 5 (+1) = 6

6 ÷ 2 = 3 remainder 0

6 ÷ 3 = 2 remainder 0

since there is a remainder of 0, when divided by 3, 6 is wrong

2) factor; 10 (+1) = 11

11 ÷ 3 = 3 remainder 2 ( 11 is not the correct answer

3) factor : 15 (+1) = 16

16 ÷ 2 = 8 remainder 0 ( 16 is  not the correct answer

4) factor : 20(+1) = 21

21 ÷ 3 = 7 remainder 0 ( 21 is wrong)

5) factor : 25(+1) = 26

26 ÷ 2 = 13 remainder 0 ( 26 is wrong)

6) factor : 30(+1) = 31

31 ÷ 2 = 15 Remainder 1

31 ÷ 3 = 10 Remainder 1

31 ÷ 5 = 6 Remainder 1

since all three divisors give a remainder of 1, the correct answer is 31

Therefore you have 31 pwnnies

answer:   b

step-by-step explanation:

x2 = 16

x can not be a negative number because 16 is positive

the only answer would be positive 8  

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204