If X^8 = (2^2)^4, what is X^2

x^2 = 4

Step-by-step explanation:

X^8 = (2^2)^4

Rewriting

x^8 as (x^2) ^4  since we know that a^b^c = a^(b*c)  and 2*4 = 8

(x^2) ^4 =  (2^2)^4

Since the exponents are the same the bases must be the same

x^2 = 2^2

x^2 = 4

-1

step-by-step explanation:

hello there!

i believe the answer is

(cot2+1)/sec2=cot2

    csc2/sec2=cot2

  (1/sin2)/(1/cos2)=cot2

  (1/sin2)(cos2/1)=cot2

  cos2/sin2=cot2

  (1/tan2)=cot2

  (cot2)=(cot2)

hope this !

hyperz ^_^