What is the slope of the line represented by the equation y = 4/5x- 3?
-3
-4/5
4/5
3

m= 4/5

Step-by-step explanation:

The equation of the line is in slope-intercept form.

y=mx+b

where m is the slope and b is the y-intercept.

Basically, the number that is being multiplied by x is the slope, and the number added or subtracted from that is the y-intercept.

We are given the equation:

y= 4/5x -3

4/5 is the coefficient of x. 3 is being subtracted from 4/5x.

Therefore, the slope of the line is 4/5 and the y-intercept is -3.

The question asks us to find the slope of the line, so the answer is 4/5.

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

yo answer should be 6 if im not mistaken

step-by-step explanation: