An arrow is shot vertically up into the air with an initial vertical velocity of 60 m/s, and its height is given by h=-5t^2+60t where h is in meters and t is in seconds. How high does the arrow go? How long does the arrow stay in flight?

The maximum height is 180 m

The arrow stay in flight for 12 seconds.

Step-by-step explanation:

We are given that An arrow is shot vertically up into the air with an initial vertical velocity of 60 m/s,

Height is given by :

Where h is the height

t is the time

We are supposed to find How high does the arrow go.

Time at maximum height :

t=6

Substitute t = 6 in the given equation of height

So,

h(6)=180

So,The maximum height is 180 m

Now we are supposed to find How long does the arrow stay in flight

So,

5t(-t+12)=0

t=12,0

So,the arrow stay in flight for 12 seconds.

answer:   x = 3 + √11     and     x = 3 - √11

step-by-step explanation:

x² - 6x + 9 = 11

(x - 3)² = 11

x - 3 = ±√11

    x = 3 ± √11

x = 3 + √11     and     x = 3 - √11