At a certain hospital, the probability of a child being born female is 0.51. If 80 babies are born on the a certain day, the probability that more than half of these babies are female is closest to? a. 0.61, b. 0.70, c. 0.39, d. 0.47, 0.53 (I will award you the brainiest)

Answer :

0.53

Step-by-step explanation:

Given the following :

Probability of female = probability of success on a single trial = 0.51

Number of babies = 80

Probability that more than half of the babies are female : p(X >80/2) = P(X > 40)

The problem can be solved using the binomial probability function :

P(X > 40) = [ p(X= 41) + p(X= 42) + +p(X= 80)]

In other to save computation time, we can use the binomial probability calculator

Hence ; P(X > 40) = 0.527 = 0.53

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it

wth is with the little mtn top and what are you talking about like fix your words and accually make sence with them and i like was in a completly different question like three times like it seems like your ilitteret