Convert the equation:
to the standard form of a hyperbola.

(x+1)²/6 - (y+3)²/12 = 1

Step-by-step explanation:

The standard form of writing the equation of an hyperbola is expressed as;

(x-h)²/a² - (y-b)²/b² = 1 where (h,k) is the centre of the hyperbola.

Given the equation:

6x²-3y²+12x-18y-3 = 0

We are to convert it to the standard form of writing the equation of a hyperbola.

Collecting the like terms will give;

(6x²+12x)-(3y²+18y)-3 = 0

Divide through by 3

(2x²+4x)-(y²+6y)-1 = 0

Completing the square of the equation in parenthesis and adding the constants to the other side of the equation:

(2x²+4x)-(y²+6y+(6/2)²)-1 = 0+(6/2)²

(2x²+4x)-(y²+6y+9)-1 = 9

2x²+4x -{(y+3)²} = 9+1

2x²+4x - (y+3)² = 10

Divide through by 2

x²+2x -(y+3)²/2 = 5

(x²+2x+(2/2)²)-(y+3)²/2 = 5+(2/2)²

(x²+2x+1) - (y+3)²/2 = 5+1

(x+1)²-(y+3)²/2 = 6

Divide through by 6

(x+1)²/6 - (y+3)²/12 = 1

The resulting equation is the required standard form of a hyperbola with centre at (-1, -3)

because they could drop even lower..

it is a. 4.2 because 7.6-3.4 gets the remaining length of 4.2. i might be wrong but i am pretty sure this is the answer.