Based on the sample of 500 people, 42% owned cats. Calculate the test statistic. Round to two decimal places.

z= 3.63

z for  significance level = 0.05 is ± 1.645

Step-by-step explanation:

Here p = 42% = 0.42

n= 500

We formulate our null and alternative hypotheses as

H0: p= 0.42     against Ha : p> 0.42 One tailed test

From this we can find q which is equal to 1-p= 1-0.42 = 0.58

Taking p`= 0.5

Now using the z  test

z= p`- p/ √p(1-p)/n

Putting the values

z= 0.5- 0.42/ √0.42*0.58/500

z= 0.5- 0.42/ 0.0220

z= 3.63

For one tailed test the value of z for  significance level = 0.05 is ± 1.645

Since the calculated value does not fall in the critical region we reject our null hypothesis  and accept the alternative hypothesis that more than 42%  people owned cats.

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step-by-step explanation: