Using a rating scale, Tekinarslan (2008) measured computer anxiety among university students who use the computer very often, often, sometimes, and seldom. Below are the results of the one-way ANOVA. Source of Variation SS df MS F Between groups 1,959.79 3 653.26 21.16* Within groups (error) 3,148.61 102 30.86 Total 5,108.41 105 (a) What are the values for N and k

k = 4 ; N = 106

Step-by-step explanation:

Given the result of the one way ANOVA :

- - - - - - - - - - - - - - - SS - - - - df - - MS - - - - - F

Between groups - 1,959.79 - 3 - - 653.26 - 21.16*

Error - - - - - - - - - - 3,148.61 - -102 --30.86

Total - - - - - - - - - - 5,108.41 - 105

To obtain the value of 'k' which is the number of groups observed :

The degree of freedom between groups or degree of freedom of treatment (DFT) is obtained by the formula:

Number of observed groups(k) - 1

DFT = k - 1

From the ANOVA result ; degree of freedom between groups = 3

Hence,

3 = k - 1

k = 3 +1 = 4

Hence, number of observed groups = 4

To obtain N;

N is related to k and the degree of freedom Error (DFE)

DFE = N - k

From the ANOVA result, DFE = 102 and k = 4

102 = N - 4

102 + 4 = N

N = 106

no association

step-by-step explanation:

if you have eyes and you can use them efficiently you can see that it just looks like random dots like do a line of best fit and like they're so spread out it's such a weak association you might as well consider it nonexistent

a.) list the factors of 40.

1/2/4/5/8/10/20/40

b.) list the factors of 40 that represent the number of cans that could be on each shelf.

5

c.) how many different arrangements of cans are possible?

just one because if you put more on one shelf you will go way over 40 and the cabinet will probably break.

d.) what are the possible arrangements of the cans?

put 5 cans on each self to reach 40 cans in total.

e.) which arrangement uses all the shelves?

5 because you can put 5 cans on each shelf, and since there are 8 shelfs you are equally going to get 40 cans.