You are playing basketball with your friends. The height (in feet) of the ball above the ground t seconds after a shot is released from your hand is modeled by the function f(t)= -16t^2 + 32t + 5.2. What is the value of t when the ball is released from your hand ?

Value of (t) = 0

Step-by-step explanation:

According to the scenario no time has passed.

t = 0

Given:

f(t)= -16t² + 32t + 5.2

When t = 0

So.

f(t)= -16t² + 32t + 5.2

f(0)= -16(0)² + 32(0) + 5.2

f(0) = 5.2 feet

because its not ur topic and its not for is for homework not that.

sorry not sure

step-by-step explanation: