Solve for bbb. \dfrac23b + 5 = 20 - b 3 2 b+5=20−bstart fraction, 2, divided by, 3, end fraction, b, plus, 5, equals, 20, minus, b b =b=b, equals

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Complete Question

Solve for b.

2/3b + 5 = 20 - b

b = 9

Step-by-step explanation:

We are given the algebraic expression

2/3b + 5 = 20 - b

Step 1

Collect like terms

2/3b + b = 20 - 5

Step 2

Solve for the left hand side of the equation

2/3b + b = 15

(5/3)b = 15

Step 3

Cross multiply

5b = 15 × 3

Step 4

Divide both sides by 5

5b/5 = 45/5

b = 9

the number of possible outcomes that do not show a 1 on the first spinner and show the number 4 on the second spinner is 2.

spinner 1 spinner 2

1                     1

1                     2

1                     3

1                     4

2                   1

2                   2

2                   3

2                   4   = not 1, and 4

3                   1

3                   2

3                   3

3                   4 = not 1, and 4

only 2 outcomes have passed the given condition.

step-by-step explanation: