The house Trevor's family lives in has 666 people (including Trevor) and 333 bathrooms. In the past month, each person showered for an average of 480480480 minutes and used an average 727272 liters of shower water (over the entire month). Water costs 0.200.200, point, 20 dollars per liter. How much did Trevor's family pay per minute on shower water?

Using proportions, we find that: Trevor's family paid $0.03 per minute on shower water.

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This question is solved using proportions.

Thus, the total amount of liters used is:

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Thus, the total amount paid was of:

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The amount of dollars per minute is:

Trevor's family paid $0.03 per minute on shower water.

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Trevor's family paid $ 1.33 per minute on shower water.

Since the house Trevor's family lives in has 6 people (including Trevor) and 3 bathrooms, and in the past month, each person showered for an average of 480 minutes and used an average 72 liters of shower water (over the entire month), and water costs 0.20 dollars per liter, to determine how much did Trevor's family pay per minute on shower water, the following calculation must be performed:

You must multiply the number of liters by its value, and divide that result by the number of minutes that each person consumed, in order to obtain the value per minute on shower water.

Therefore, Trevor's family paid $ 1.33 per minute on shower water.

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∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.