2. A woman travelled from Lagos to Ondo a distance of 350km. Her average speed on the outward journey was ykm. On the return journey, her average speed was 10km/hr faster and therefore she completed the return journey 37.5minutes earlier. Find A. The value of y B. Get average speed on the return journey in km/hr C. The total time taken for the whole journey in hrs. Good luck

70 km/h

9 hr 22.5 min

Step-by-step explanation:

Given

Difference in time as equation:

Average speed was 70 km/h

Total time = 350/70 + 350/(70+10) = 5 + 4.375 = 9.375 hr = 9 hr 22.5 min

the inequality is:

250c+180g≥950

step-by-step explanation:

let c denotes the number of days in a week   miyoko worked as a cryptographer.

and g denotes the number of days in a week she works as a geologist.

now we are given that she earns $250 for every day she works as a cryptographer,and earns $180 for every day she works as a geologist.

now miyoko's goal is to earn more than $950 this week.

hence, the inequality could be represented as:

250c+180g≥950

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5