Two years ago a woman was 7 times as old as the girl how old are they now

The woman is 37 years old, and the girl is 7 years old

Step-by-step explanation:

It seems that problem is incomplete. The complete question is:

"two years ago a woman was 7 times old as her daughter, but in 3 years time she would be 4 times old as the girl. how old are they now​"

So we can create 2 equations with 2 unknowns:

If W is the woman's current age, and g is the girl's current age, then we can write for the first statement :

"two years ago a woman was 7 times old as her daughter"

W - 2 = 7 * (g - 2)

W = 2 + 7 g -14

W = 7 g - 12

Now the second equation:

"in 3 years time she would be 4 times old as the girl"

W + 3 = 4 (g + 3)

W = 4 g + 12 - 3

W = 4 g + 9

Now we make the two equations equal via W:

7 g - 12 = 4 g + 9

3 g = 21

g = 7

and therefore, the current woman's age is:

W = 7 (7) - 12 = 49 - 12 = 37

x= 149. 24+7=31. 180-31=149

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