Hello, I need some help resolving this problem of Trigonometric Identities. Use the reciprocal identities to resolve it SinA+cosA*cotA= cscA

Please see steps below

Step-by-step explanation:

Start by writing all trig functions in the equation in terms of their simplest forms using the two basic trig functions: :

Now work on the left side (which is the most complicated one), trying to simplify it using the properties for adding fractions with different denominators:

where in the last step we have used that the Pythagorean identity for:

Notice that we arrived at the expression: , which is exactly what appears on the other side of the initial equation/identity we needed to prove, so the prove has been completed.

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0