What is the decibel level of a dog barking with intensity 10−5 watts per square inch? Use a logarithmic model to solve.

70 dB

Step-by-step explanation:

D=10log(I10−12)

Substitute in the intensity level, I, and then simplify to find

DD=10log(10−510−12)=10log(107).

Since log107=7, simplify to find

DD=10⋅7=70.

The decibel level is 70dB.

the simplified form is

step-by-step explanation:

we want to simplify the expression,

let us change the middle bar to a normal division sign to obtain,

we multiply the first fraction by the reciprocal of the second fraction to obtain,

we factor to obtain,

we cancel the common factors to get,

we simplify to get,

the correct answer is b