PLEASE HELP In the figure below, ∠DEC ≅ ∠DCE, ∠B ≅ ∠F, and DF ≅ BD. Point C is the point of intersection between AG and BD while point E is the point of intersection between AG and DF. Prove ΔABC ≅ ΔGFE.

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∠ABC ≅ ∠DEC

∠DEC = ∠GEF

thus:

∠ABC = ∠GEF

∠GFE ≅ ∠DCE

∠DCE = ∠ACB

thus:

∠ACB = ∠GFE

If two of their angles are equal, then the third angle must also be equal, because angles of a triangle always add to make 180°.

Thus: ΔABC ∼ ΔGEF by AA similar triangle postulate.

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ItsNobody~ ☆

g(x) = x² + 2

step-by-step explanation:

it is given that the graphs are the same shape.

the only difference is that the red graph is 2 units higher than the blue graph.

that is to say that the red graph is simply the blue graph that has been moved vertically by 2 units in the positive y direction.

hence

g(x) = f(x) + 2

or

g(x) = x² + 2