OABCD is a pyramid with a rectangular base of sides 15cm by 9cm. Given that the slant height OQ is 16cm find its i)height
ii)volume

Hello! Your answer is below... Remember : h = height and v = volume

H = 15.35 cm

V = 690.75 m^

Step-by-step explanation:

(H= height, V = volume, ^= square, √ = square root )

1. divide 9/2

=4.5 cm

2. use the pythagorean theorem

H=√16^-4.5^

H=15.35

if your looking for volume

1. use the formula for volume of the pyramid which is:

1/3 x base area x height

or

base area x height /3

2. then you substitute

1/3 x (9)(15) x 15.35

or

(9)(15) x 15.35 /3

V= 690.75 m^

Hope it helped u if yes mark me BRAINLIEST!

Tysm!

:)

height =  h = 13.4 cm

volume =  V = 602.8 cm³

Step-by-step explanation:

area of a square base = 15 cm x 9 cm = 135 cm²

slant height of pyramid = 16m

solving height:   (see attached image)

first step is to take the diagonal base:

side of base 15 =  15 / 2 = 7.5cm

side of base 9 = 9 / 2 = 4.5m

diagonal base = sqrt ( 7.5² + 4.5²) = 8.75 cm

therefore

height² = slant height² - diagonal base²

h² = 16² - 8.75²

h = 13.4 cm

solving the volume:

V = 1/3 * area of square base * h

V = 1/3 * 135 * 13.4

V = 602.8 cm³

astronomers is your final answer! : )

answer: huh

step-by-step explanation: