A new Community Sport complex is being built in safe harbor the perimeter of the rectangular playing field is 402 yards the length of the field is 9 yards less than quadruple the width what are the dimensions of the playing field?

Step-by-step explanation:

Perimeter of a rectangle = 2l + 2w

where

l is the length

w is the width

From the question

Perimeter = 402 yards

The statement

the length of the field is 9 yards less than quadruple the width is written as

l = 4w - 9

Substitute this is expression into the above formula and solve for the width

That's

402 = 2( 4w - 9) + 2w

402 = 8w - 18 + 2w

10w = 402 + 18

10w = 420

Divide both sides by 10

Substitute this value into l = 4w - 9

That's

l = 4(42) - 9

l = 168 - 9

Therefore

length = 159 yards

width = 42 yards

Hope this helps you

  y= -3x is the required function.

step-by-step explanation:

we have been given a table:

x             y

0             0

1             -3

3             -9

-2             6

we can see that the values of y is -3 times the value of x

hence, the function would be: y= -3x.

put the values of x will give the same y as in the table that means function is satisfying the given table.