The maximum horizontal range of a projectile is given by the formula where u is the initial velocity and g is the acceleration due to gravity. Find the velocity with which a ball can be thrown to have a maximum range of 20 meters when the acceleration due to gravity is equal to 9.8 m/s.

v=?

U=0

a=9.8m/s²

s=20m

V²=u+2as

v²=0+2*9.8*20

v²=392

v=✓392

v=19.789

v=19.80m/s

3201

step-by-step explanation:

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

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