What is the equation of the line that passes through the point (2, -1) and has a slope of
3/2

The answer is

Step-by-step explanation:

To find the equation of the line using a point and slope we use the formula

where m is the slope

(x1 ,y1) is the given point

From the question

slope = 3/2

point = ( 2 , - 1)

Substitute these values into the above formula

That's

We have the final answer as

Hope this helps you

y= 3/2x -4

Step-by-step explanation:

Since we are given a point and a slope, we can use the point-slope formula.

where m is the slope and (x1, y1) is a point the line passes through.

We know the slope is 3/2 and the point we are given is (2, -1).

Substitute the values into the formula.

We want to find the equation of line , which is y=mx+b ( m is the slope and b is the y-intercept). Therefore, we must get y by itself on the left side of the equation.

First, distribute the 3/2. Multiply each term inside the parentheses by 3/2.

Next, subtract 1 from both sides.

Now the line is in slope intercept form, therefore the equation of the line is y=3/2x -4. The slope of the line is 3/2 and the y-intercept is -4.

its kind of blurry. can you put a clearer pic?

step-by-step explanation: