Integrate the function F(x, y,z)=6z over the portion of the plane x+y+z=4 that lies above the square , in the xy-plane. integral integral_S F(x, y, z) d sigma =

Arectangle has a width of 5 cm and a length of 10 cm. if the width is increased by 3, how does the perimeter change?

How is the equation of this circle written in standard form? x2 + y2 - 6x + 14y = 142 a) (x - 3)2 + (y + 7)2 = 200 b) (x+ 3)2 + (y - 7)2 = 200 (x - 6)2 + (y + 14)2 = 142 d) (x+6)2 + (y- 14)2 = 142

If /is a line of symmetry, plot the partner points for the ones shown. noch 6 5 4 -3 -2 -1