If AD is the altitude to BC, what is the slope of AD?
C(3,8)
D
A(0,1)
B(7,-2)

B. 2/5

Step-by-step explanation:

From A to C you go 3 right and 7 up.

From A to B you go 3 down and 7 right.

That makes AC and AB congruent and you have an isosceles triangle.

This makes D the midpoint of segment BC.

D( (7 + 3)/2, (8 - 2)/2) = D(5, 3)

The slope of segment AD is:

Using points A(0, 1) and D(5, 3)

(y2 - y1)/(x2 - x1) = (3 - 1)/(5 - 0) = 2/5

m=4/10=2/5

Step-by-step explanation:

since Ab is perpendicular to BC

m1*m2=-1

the slope of perpendicular lines has reciprocal opposite slope slope

slope of line BC C(3,8)  B(7,-2)

m=y2-y1/x2-x1

m=-2-8/7-3

m=-10/4

-10/4 m =-1

-10m=-4

m=-4/-10

m=4/10

47

step-by-step explanation: