Please help. pls show workings

≈ 10.52 cm²

Step-by-step explanation:

The unshaded area is calculated as area of square subtract area of quarter circle, thus

A = 7² - πr²

   = 49 - ( 0.25π × 7²)

   = 49 - (0.25π × 49)

   = 49 - 12.25π

   ≈ 10.52 cm² ( to 2 dec. places )

10.5cm^2

Step-by-step explanation:

Area of the square = L^2 =(7) ^2=49cm^2

Radius of quadrant = 7cm

Area of the quadrant =1/4 x πr^2

1/4 x 22/7 x (7) ^2

1/4 x 22/7 x 49

=38.5cm^2

Area of unshaded part= area of square - area of quadrant

49cm^2 - 38.5cm^2

=10.5cm ^2

δabc ≅ δdcb by sas because

db ≅ ac . . given (side)

bc ≅ bc . . reflexive property (side)

∠dbc ≅ ∠ acb . . alternate interior angles where transversal bc crosses parallel lines bd and ac (included angle)