HELPP ASAP NEEDED MATH There are $20n$ members in the Trumpington marching band, and when they line up in rows of 26, there are 4 band members left over. If $n$ is an integer and there are fewer than 1000 band members, what is the maximum number of people that could be in the Trumpington marching band?

992

Step-by-step explanation:

Divide 1000 by 26.

The answer is 38 and some left over. We don't care what the leftover is because it is nearly 0.5 and that means 13 people were left over.

Take the integer value (38) and multiply it by 26. You get 988.

You want there to be 4 left over. 4 + 988 = 992. That's one way of doing the problem.

940 people is the maximum

Explanation:

n = 1 means 20n = 20*1 = 20 members total, which is 4 short of making a row of 26 (so the remainder is 20)

n = 2 means 20n = 20*2 = 40 members. 40/26 = 1 remainder 14. We could make one full row with 14 members left over.

20n < 1000 solves to n < 50 after dividing both sides by 20. This means n is smaller than 50. It has to be larger than 0 or else 20n would be 0 or negative. We can write 0 < n < 50 to specify the range for n.

Since n < 50, this means the largest n can get is n = 49.

If n = 49, then 20n = 20*49 = 980

980/26 = 37 remainder 18, which isn't the remainder we want (of 4).

If n = 48, then 20n = 20*48 = 960

960/26 = 36 remainder 24, again not the remainder we want

If n = 47, then 20n = 20*47 = 940

940/26 = 36 remainder 4

If we have 940 members, then we can form 36 rows (26 in each row). So 26*36 = 936 people so far. Then we have 940-936 = 4 people left over.

There are other solutions as well such as n = 34, n = 21, and n = 8. Though n = 47 is the largest n possible to fit all the conditions required.

.24

step-by-step explanation:

the probability is   .24

the first player had the highest probability of getting a silver marble

the game could be made fair by adding back the marble that was drawn after each draw

560

hope this : )