A ship sails 95 km on a bearing of 140 degrees, than further on 102km on a bearing of 260degrees, and than returns directly to its starting point. Find the length and bearing of the return journey

1. 98.7 km

2. 303.5 degree

Step-by-step explanation:

Using the alternate angle, the angle at B will be 50 + 10 = 60 degree.

To calculate the length AC of the returning journey, use cosine formula to calculate it.

To find the bearing of the returning journey, use sine rule to calculate it.

Please find the attached file for the solution

i believe the answer is c.

its the second choice.

step-by-step explanation:

the elements in the range will be 7 less than the elements in the domain.