The length of time it takes college students to find a parking spot in the library parking lot follows a normal distribution with a mean of 6.5 minutes and a standard deviation of 1 minute. Find the probability that a randomly selected college student will find a parking spot in the library parking lot in less than 6.0 minutes.

P(X<6) = 0.3085 or 30.85%

Step-by-step explanation: Determine, first, z-score:

x is a random variable for time a student takes to find a spot, in this case, x=6:

z = -0.5

Using z-score table, find z-score:

P(X<6) = P(z< -0.5)

P(X<6) = 0.3085

Probability of finding a parking spot in less than 6 minutes is approximately 30.85%.

it would more likely be bald eagle because its has more in the box so about 75%.

step-by-step explanation: