What is the area of a regular hexagon with an apothem 16.5 inches long and a side 19 inches long? Round the answer to the nearest tenth. A. 625.3 in.2 B. 940.5 in.2 C. 156.3 in.2 D. 1,875.8 in.2

Explanation:

Any regular hexagon is really the combination of six identical (aka congruent) equilateral triangles glued together. If we can find the area of one triangle, then we multiply by 6 to get our final answer.

The apothem is the height of the equilateral triangle with the triangular base being the side length of the hexagon.

area of triangle = (1/2)*base*height

area of triangle = 0.5*(hexagon side length)*(apothem)

area of triangle = 0.5*19*16.5

area of triangle = 156.75

This is the area of one equilateral triangle. Having 6 triangles leads to a total area of 6*156.75 = 940.5 square inches

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.

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step-by-step explanation:

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