Web site W receives orders for its products every day. What is the standard deviation of the numbers of orders that Web site W received daily for the past 5 days?(1) The average (arithmetic mean) number of orders that Web site W received per day for the past 5 days is equal to the greatest of the numbers of orders that Web site W received daily for the past 5 days.(2) The range of the numbers of orders that Web site W received daily for the past 5 days is equal to 0.

The standard deviation is zero

Step-by-step explanation:

Given that:

Web site W receives orders for its products every day.

What is the standard deviation of the numbers of orders that Web site W received daily for the past 5 days?

If :

(1) The average (arithmetic mean) number of orders that Web site W received per day for the past 5 days is equal to the greatest of the numbers of orders that Web site W received daily for the past 5 days.

SO, IF the average (arithmetic mean) is greatest , therefore, this implies that the  number of orders per day remains the same. Then the standard deviation will be zero because the set of values for the number of orders per day for the five days is the same.( i.e contains identical numbers).

.(2) The range of the numbers of orders that Web site W received daily for the past 5 days is equal to 0.

The range is the difference between the greatest value and the smallest value.

i.e

greatest value -  smallest value = 0

greatest value =  smallest value

Therefore , the range is zero and the standard deviation will remain the same (zero)

there are lots of ways.   pick's theorem tells us if the vertices are lattice points the area a is

a = b/2 + i - 1

where b is the number of boundary lattice points and i is the number of interior lattice points.

in the figure i count b=16, i=50 so

a = 8 + 50 - 1 = 57

let's try the shoelace formula.   the area is half the sum of the cross products of the sides.  

a(-2,6)   -2(2)-6(-5) = 26

b(-5,2)   -5(-3) - 2(-2) = 19

c(-2,-3) -2(-3) - (-3)(4) = 18

d(4,-3)   4(3) - (-3)(5) = 27

e(5,3)   5(3) - 3(1) = 12

f(1,3)     1(6) - 3(-2) = 12

a(-2,6)

each of the cross products is twice the area of the triangle with the associated side and one vertex the origin. so the area of abo=26/2=13.

area = (1/2) (26 + 19 +   18 + 27 + 12 + 12) = 57

that checks!

answer: (-6,3)

step-by-step explanation: