The sum of Rhonda and her daughter Tenica’s age is 64. The difference in their ages is 28. How old is each person?

The mother (Rhoda) is 46 years old.

The daughter (Tenica) is 18 years old

Step-by-step explanation:

Let the age of the mother (Rhoda) be m

Let the age of the daughter (Tenica) be d.

The sum of Rhonda and her daughter Tenica’s age is 64. This can be written as:

m + d = 64 ... (1)

The difference in their ages is 28. This can be written as:

m – d = 28 ... (2)

From the above illustrations, the equation obtained are:

m + d = 64 ... (1)

m – d = 28 ... (2)

Solving by elimination method:

Add equation 1 and 2 together

. m + d = 64

+ m – d = 28

¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯¯

2m = 92

Divide both side by 2

m = 92/2

m = 46

Substitute the value of m into any of the equation to obtain the value of d. Here, we shall use equation 1

m + d = 64

m = 46

46 + d = 64

Collect like terms

d = 64 – 46

d = 18

Therefore, the mother (Rhoda) is 46 years old and the daughter (Tenica) is 18 years old.

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