n a genetics experiment on peas, one sample of offspring contained 372 green peas and 35 yellow peas. Based on those results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of 3 4 that was expected?

Complete Question

In a genetics experiment on peas, one sample of offspring contained 372 green peas and 35 yellow peas. Based on those results, estimate the probability of getting an offspring pea that is green. Is the result reasonably close to the value of 3/4 that was expected?

The  probability is  

No it is not close to the probability expected

Step-by-step explanation:

From the question we are told that

    The sample size is  

      The  number of  green peas is  

    The  number of  yellow  peas is  

The  probability of getting an offspring pea that is green is mathematically represented as

substituting values

The  expected probability is  

But what we got is  

So we can say that the value obtained is not equal to the expected value

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.