Missing Portion on Spinner: So theres a circle,

2/3 is covered,

1/6 is covered,

and 1/9 is covered

what fraction is the portion that isn't covered

Explanation:

The fractions 2/3, 1/6 and 1/9 have the denominators 3, 6 and 9. The LCM is 18, so the LCD of the fractions is 18.

2/3 = 12/18 after multiplying top and bottom by 6

1/6 = 3/18 after multiplying top and bottom by 3

1/9 = 2/18 after multiplying top and bottom by 2

The three original fractions 2/3, 1/6, and 1/9 are equivalent to 12/18, 3/18, and 2/18 in that exact order.

With the fractions all having the same denominator, we can add the numerators to place over the common denominator

12/18 + 3/18 + 2/18 = (12+3+2)/18 = 17/18

After combining all of the shaded areas, we have 17/18 of the circle shaded in with 1/18 of the circle not shaded in.

You subtract 17/18 from 1 to get 1/18

1 - (17/18) = 18/18 - 17/18 = (18-17)/18 = 1/18

You could think of it like having 18 slices of cake total, and 17 are eaten by guests, so 18-17 = 1 is left over out of the 18 overall. So 1/18 of the cake hasn't been eaten.

answer: options?

step-by-step explanation:

-3

step-by-step explanation:

a drawing really does here:

so i draw the horizontal line y=2 and the vertical line x=-2 at this intersection i put b (this is where my right angle is going to be).   so point b is at (-2,2).   point a is 5 units long and is also on y=2 so this point has to be (3,2) or (-7,2) -doesn't matter i will go with (3,2).

now we know c is at (-2,y) we don't know the y yet bet we know that c is on x=-2.

we have the area of the triangle is .5bh=12.5

we know the base length is 5 (ab)

we have the height is (2-y) if you look at your

plug in

.5(5)(2-y)=12.5

solve for y to get the y-coordinate for c

2.5(2-y)=12.5

divide both sides by 2.5 giving:

2-y=5

now subtract 2 on both sides

-y=3

y=-3