how many unique 10 digit numbers can be formed if the number 2 is in the first place and repetition is allowed?

362880 ways

Step-by-step explanation:

Given

10 digits

Required

Number of 10 digits that can be formed if no repetition and 2 must always start;

Since digit 2 must always start and no repetition is allowed, then there are 9 digits left

Digit 2 can only take 1 position

9 digits can be arranged without repetition in 9! ways;

Calculating 9!

Number of arrangement  = 1 * 362880

Number of arrangement  = 362880 ways

y=3n + 1

step-by-step explanation:

this is wrong because it says the second number is one less and i added one instead

hi! i think the answer is 1/2 : )