Two buildings are 12m apart on the same horizontal level. From the top of the taller building, the angle of depression of the bottom of the shorter building is 48degrees and from the bottom, the angle of of elevation of the top of the shorter building is 36 degrees. Calculate the difference in the heights of the buildings

2.08 meters

Step-by-step explanation:

From the diagram attached :

We can calculate the height of the shorter building using trigonometry :

s = Height of shorter building

t = height of taller building

Tanθ = opposite / Adjacent

θ = 36°

Adjacent = 12, opposite = s

Tan36° = s / 12

0.7265425 × 12 = s

s = 8.72 meters

s = height of shorter building 8.72 meters ( 2 decimal places)

Height of taller building :

Tanθ = opposite / Adjacent

θ = 48°

Adjacent = t ; opposite = 12

Tan48° = 12 / t

1.1106125 = 12 / t

1.1106125 × t = 12

t = 12 / 1.1106125

t = 10.80 meters ( 2 decimal places)

Height of Taller building = 10.80 meters

Difference in height :

(10.80m - 8.72m) = 2.08 meters

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it