The Rocky Mountain district sales manager of Rath Publishing Inc., a college textbook publishing company, claims that the sales representatives make an average of 43 sales calls per week on professors. Several reps say that this estimate is too low. To investigate, a random sample of 29 sales representatives reveals that the mean number of calls made last week was 44. The standard deviation of the sample is 4.1 calls. Using the 0.050 significance level, can we conclude that the mean number of calls per salesperson per week is more than 43? H0: μ ≤ 43 H1: μ > 43 Compute the value of the test statistic. (Round your answer to 3 decimal places.)

The critical region for α= 0.05 is Z > ± 1.645

The calculated value of Z= 1.100

Step-by-step explanation:

The null and alternate hypotheses are given

H0: μ ≤ 43

H1: μ > 43  one tail test

∝= 0.05

n= 29

Standard Deviation= s= 4.1

Mean = μ0 = 44

For one tail test the z value of α= ± 1.645

The critical region for α= 0.05 is Z > ± 1.645

The test statistic is given by

z=μ0-μ/ s/√n

Z= 44-43/4.1/√29

Z= 1/4.1/√29

Z= 1.100

Since the calculated value Z= 1.100 does not  fall in the critical region , We reject H0 and may conclude that the mean number of calls per salesperson per week is not more than 43

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

answer: no

step-by-step explanation: because the big angle will spread away the 2 side that it is on and make the opposite side even longer.