determine whether the series is absolutely convergent, conditionally convergent, or divergent sin(n)/3^n convergent

absolutely convergent

Step-by-step explanation:

given data

sin(n)/3^n

solution

we have given term

when n = 1

and we know that

value of sin(n) ≤ 1

so that we can say that

 ≤   or

here  is converges this is because common ratio in geometric series

here r is  and here it satisfy that -1 < r < 1

so it is converges

and

 is also similar

so it is  converges

and here no  term is

so we can say series is absolutely convergent

step-by-step explanation:

the answer is a i belaeve atleast thats what my calculator just gfave me

step-by-step explanation: