If f(x)=ax^2+bx+c and f(0)=-4 and f(1)=-2 and f(2)=6, what is the value of A and B and C?

Hello There!!

I'm not a 100% sure this right.

Step-by-step explanation:

f(x)=ax2+bx+c for which f(1)=0, f(-2)=6 and f(2)=-14

0 = a +b +c

6 =4a -2b +c

-14=4a+2b +c

subtract third equation from second to get

20 = -4b and so b=-5

first equation is now 5 = a+c

second is now -4=4a+c

subtract to get -9=3a and so a=-3

equation one now is 0=-3-5+c or c=8 Hope This Helps!!

answer: r there any options?

step-by-step explanation:

b) 1/3 * 1/5

step-by-step explanation:

each smallest part is 1/15 since the written one is 1/5 and it's divided by 3 equal parts. (1/5 )/3 = 1/15 = 1/3 * 1/5