GIVING 30 POINTS!! Find the perimeter of the following shape, rounded to the nearest tenth A at -3,2, B at -1,0 C at -3,-2 and D at -5,0 A) 8 B) 11.3 C) 12 d)17.9

B = 11.3 units

Step-by-step explanation:

Hi, I'm guessing the numbers you've given are the coordinates of the different points on a graph.

Step. 1

I would draw the graph, as it makes it easier to visualise. I have drawn a rough sketch of it, and I'm glad I did, because now it's much clearer that the shape is a square. A square has 4 sides of the same length, which means that we only have to find the length of one of the sides, then multiply that by 4.

Step 2.

We can see that the difference between all the points is 2 horizontal units and 2 vertical units. If we imagine the difference between the two points as a triangle (a line going horizontal 2 units and then vertical 2 units, with the hypotenuse being the actual length we want to find), we can use Pythagoras' theorem.

Pythagoras' theorem is a² + b² = h², meaning that side A squared added to side B squared equals the square of side Hypotenuse.

Side A is 2 units across and side B is 2 units across (as measured on the graph), so 2² + 2² = 4 + 4 = 8.

Now the answer we have here is the square of the side we're looking for. √8 = 2.82842 which is the length of one side of the shape.

Step 3.

We know that all 4 sides are the same length, so we can do 2.82842... x 4 = 11.31368 Since the answer must be rounded to the nearest tenth, the answer is 11.3 units.

Step 4.

The option for 11.3 units is B.

Hope this helped!

Bluey :)

just needed some points but try socratic