The given line segment has a midpoint at (-1, -2). What is the equation, in slope-intercept form, of the
perpendicular bisector of the given line segment?
ch
4
3
O y=-4x - 4
O y = -4x - 6
O y=x-4
2
1
х
5 4 -3 -2 -11
61,-2)
Oy=+x-6
234
(3.-1).
-3
(-5, 3)
w5

  y = -4x -6

Step-by-step explanation:

The given segment has a rise if 1 for a run of 4, so a slope of ...

  m = rise/run = 1/4

The desired perpendicular has a slope that is the negative reciprocal of this:

  m = -1/(1/4) = -4

A point that has a rise of -4 for a run of 1 from the given midpoint is ...

  (-1, -2) +(1, -4) = (0, -6) . .  . . . . . the y-intercept of the bisector

So, our perpendicular bisector has a slope of m=-4 and a y-intercept of b=-6. Putting these in the slope-intercept form equation, we find the line to be ...

  y = mx +b

  y = -4x -6

i would say the third one.

step-by-step explanation: liner would mean in a line and the only one that doesn't look like it's even thinking about forming a line would be the third one

hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6