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Measure of arc CD = 112°

Step-by-step explanation:

Since quadrilateral ABCD is a cyclic quadrilateral,

m∠A + m∠C = 180°

129° + m∠C = 180°

m∠C = 180° - 129°

m∠C = 51°

Since, m(arc BD) = 2(m∠C) [Since measure of the arc is double of its inscribed angle]

                           = 2(51°)

                           = 102°

Since, m(arc BD) + m(arc CD) + m(arc BC) = 360°

102° + m(arc CD) + 146° = 360°

m(arc CD) = 360° - (102° + 146°)

                = 112°

Therefore, measure of arc CD is 112°.

the answer is d

step-by-step explanation:

y+3=-4(x-2)

y+3=-4x+8

  -3         -3  

y=-4x+5