The axis of symmetry for a quadratic equation can be found using the formula x equals StartFraction negative b Over 2 a EndFraction, where a and b are coefficients in the quadratic equation and x represents the values along a vertical line on the coordinate plane. What is the equation when solved for a?

The value of a when solved from x = -b/2a is;

a = -b/2x

We are given the formula for axis of symmetry of a quadratic equation to be;

x = -b/2a

Where;

a and b are coefficients in the quadratic equation

x represents the values along a vertical line on the coordinate plane.

Now, we want to solve for a which means we make it the subject of the equation;

Using multiplication property of equality, we multiply both sides by 2a to get;

2ax = -b

We now use division property of equality by dividing both sides by 2x to get;

a = -b/2x

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Step-by-step explanation:

The equation of a quadratic function is given as:

ax² + bx + c = 0

where a, b and c are the coefficient in the quadratic equation.

The axis of symmetry of the quadratic equation is given as:

To get the equation for a, we have to make a the subject of formula:

gregory's graph is incorrect because it shows 2 inches of growth for each week when it should show 0.75 inches of growth each week.

if the eqn of the parabola is f(x) = (x-4)(x+2), we need to mult. this out to find the coordinates of the vertex.

then f(x) = x^2 + 2x - 4x - 8, and f(x) = x^2 - 2x - 8.

one way in which you can find the vertex is to calculate x = -b / (2a).   here, that comes to

        )

x = = 1.   f(1) = 1^2 - 2(1) - 8 = - 9.   vertex is at (1, -9).

        2(1) 

find another point on the curve:   let x=0, for which y=-8.   then (0, -8) is on the curve.   plot the vertex and this point and draw a smooth parabola thru both.

hope this