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A line passes through point (–6, –1) and is parallel to the equation y = –2x – 5. What's the equation of the line?

Question 25 options:

y = –2x – 13

y = 12{"version":"1.1","math":"\( \frac{1}{2}\)"}x + 3

y = –12{"version":"1.1","math":"\(\frac {1}{2}\)"}x – 1

y = 2x + 5

click on picture for a, b, c ,or d

y=−2x−13.

Step-by-step explanation:

The equation of the line in the slope-intercept form is y=−2x−5.

The slope of the parallel line is the same: m=−2.

So, the equation of the parallel line is y=−2x+a.

To find a, we use the fact that the line should pass through the given point: −1=(−2)⋅(−6)+a.

Thus, a=−13.

Therefore, the equation of the line is y=−2x−13.

example 2 – simplify: step 1: completely factor both the numerators and denominators of all fractions. step 2: change the division sign to a multiplication sign and flip (or reciprocate) the fraction after the division sign; essential you need to multiply by the reciprocal. step 3 : cancel or reduce the fractions.

my guess is

step-by-step explanation: